4k^2-40k=0

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Solution for 4k^2-40k=0 equation: 



4k^2-40k=0

a = 4; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·4·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*4}=\frac{0}{8}
=0
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*4}=\frac{80}{8}
=10
$

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